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		<title>liraland.com [Topic: Accounting for non-linearity in the slab]</title>
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		<pubDate>Tue, 21 Apr 2026 11:45:58 +0300</pubDate>
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			<title>Accounting for non-linearity in the slab</title>
			<description><![CDATA[<b><a href="http://www.liraland.com/forum/messages/forum3/topic1795/message12819/">Accounting for non-linearity in the slab</a></b> in forum <a href="http://www.liraland.com/forum/forum3/">General Discussion</a>. <br />
			How to calculate the area of distributed horizontal reinforcement? Cross-section 1000x250(h) (FE210). The diameter of reinforcement equal to 20 mm with the step 150 mm. Is there great difference when calculating a corner reinforcement? <br />
			<i>Apr 28, 2015 16:02:02, Ëåîíèä.</i>]]></description>
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			<pubDate>Sun, 28 Dec 2014 16:02:02 +0200</pubDate>
			<category>General Discussion</category>
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			<title>Accounting for non-linearity in the slab</title>
			<description><![CDATA[<b><a href="http://www.liraland.com/forum/messages/forum3/topic1795/message12780/">Accounting for non-linearity in the slab</a></b> in forum <a href="http://www.liraland.com/forum/forum3/">General Discussion</a>. <br />
			Thank you! <br />
			<i>Apr 20, 2015 14:21:58, zz926.</i>]]></description>
			<link>http://www.liraland.com/forum/messages/forum3/topic1795/message12780/</link>
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			<pubDate>Sat, 20 Dec 2014 14:21:58 +0200</pubDate>
			<category>General Discussion</category>
		</item>
		<item>
			<title>Accounting for non-linearity in the slab</title>
			<description><![CDATA[<b><a href="http://www.liraland.com/forum/messages/forum3/topic1795/message12779/">Accounting for non-linearity in the slab</a></b> in forum <a href="http://www.liraland.com/forum/forum3/">General Discussion</a>. <br />
			Hello, <a class="blog-p-user-name" id="bp_FdGNxz14" href="/forum/user/24418/" bx-tooltip-user-id="24418">zz926</a>! <br /><br />1) You may use FE 241, 242 and 244 for the calculation. I recommend you to get familiar with the library of finite elements in the reference. There is a lot of useful information. &nbsp;<br /><br />2) The calculation is very easy. You have to multiply the area of reinforcement bar (1.131 cm2) by the number of bars that will be placed of one running miter of cross-section. If the step of bars is 200 mm then it will equal to 5 bars. Divide the given value by 100cm, ie “spread” reinforcement on the 1 miter length of the cross-section. &nbsp;Total we obtain 0.05655 cm. <br />
			<i>Apr 20, 2015 12:14:42, alekstish.</i>]]></description>
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			<pubDate>Sat, 20 Dec 2014 12:14:42 +0200</pubDate>
			<category>General Discussion</category>
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			<title>Accounting for non-linearity in the slab</title>
			<description><![CDATA[<b><a href="http://www.liraland.com/forum/messages/forum3/topic1795/message12767/">Accounting for non-linearity in the slab</a></b> in forum <a href="http://www.liraland.com/forum/forum3/">General Discussion</a>. <br />
			Hello, there is a necessity to calculate the plate taking into account nonlinearity. <br />The program says “Stiffness type is not appropriate to FE type”<br />1. which FE is correct in this case?<br />2. on the tab stiffness and materials/stiffness for plate/type of reinforcement there is a button “bar reinforcement (physical equivalent of grid)” it is required to set Hy and Hx. If I have grid with diameter of 12mm and step 200mm along x and y axis. Which values do I need to specify for Hy and Hx? <br />
			<i>Apr 17, 2015 15:09:09, zz926.</i>]]></description>
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			<pubDate>Wed, 17 Dec 2014 15:09:09 +0200</pubDate>
			<category>General Discussion</category>
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